ARS conf

1. Brekeke Product Name and version: Brekeke PBX, Version 2.1.6.6

2. Java version:

3. OS type and the version:

4. UA (phone), gateway or other hardware/software involved:

5. Select your network pattern from http://www.brekeke-sip.com/bbs/network/ ... terns.html :

6. Your problem:
There is a problem.
How to connect two ippbx to be able to communicate among themselves?
Such as the one pbx numbers begin with 7, while the other 2.
Both pbx are in the same subnet.
where and what to prescribe in order to be able to call?

Thanks

make an ARS - pattern OUT at pbx numbers begin with 7
matching patterns:
To: sip:(2.+)@

Deploy patterns:
To: sip:$1@ the other pbx IP

at the pbx numbers begin with 2
matching patterns:
To: sip:(7.+)@

Deploy patterns:
To: sip:$1@ the other pbx IP

you can also use dial plan

Thank Hope

With the settings that you recommended the return errors 407
Proxy Authentification Required.
I solved the problem this way:
on the PBX B (rooms start at 2) created a number of 700 (or any other) and at the PBX A (Rooms start at 7) wrote that ARS

pattern OUT

matching patterns
from sip:(7.+)@
to sip:(2.+)@

deploy pattens
from sip:700@
to sip:$1@ip pbx b

Once again, thank you